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Question 600314
JEE Chemistry · Hard

Chemical Bonding: VSEPR lone pairs MCQ

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VSEPR lone pairsHardQuestion 600314

Question

The bond angle in H₂O (2 bond pairs, 2 lone pairs) is approximately:
  1. A
    120°
  2. B
    109.5°
  3. C
    104.5°
    Correct
  4. D
    107°

Correct answer

104.5°

Explanation

H₂O: 4 electron pairs. Tetrahedral electron geometry but bent molecular shape. Two lone pairs (stronger repulsion) compress the bond angle from 109.5° to 104.5°.

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