ΔG and EMFMediumQuestion 710008
Question
The relationship between ΔG° and E°cell is:
- AΔG° = −nFE°cellCorrect
- BΔG° = nFE°cell
- CΔG° = −RTlnK
- DΔG° = −E°cell/nF
Correct answer
ΔG° = −nFE°cell
Explanation
ΔG° = −nFE°cell, where n = moles of electrons transferred, F = Faraday constant (96485 C/mol). Combining with ΔG° = −RTlnK gives E°cell = (RT/nF)lnK.