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JEE Chemistry · Medium

Electrochemistry: Faraday's second law MCQ

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Faraday's second lawMediumQuestion 710009

Question

When the same charge passes through AgNO₃ and CuSO₄ solutions, the ratio of Ag:Cu deposited (by moles) is:
  1. A
    2:1
    Correct
  2. B
    1:2
  3. C
    1:1
  4. D
    3:1

Correct answer

2:1

Explanation

Faraday's Second Law: masses deposited are proportional to equivalent weights. n-factor of Ag⁺ = 1, n-factor of Cu²⁺ = 2. For same charge: moles Ag = 2 × moles Cu. Ratio Ag:Cu = 2:1.

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