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JEE Chemistry · Medium

Electrochemistry: Electrolysis calculation MCQ

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Electrolysis calculationMediumQuestion 710010

Question

0.965 A current passes for 100 s through CuSO₄ solution. Mass of Cu deposited (M = 64, n = 2) is:
  1. A
    0.032 g
    Correct
  2. B
    0.64 g
  3. C
    0.128 g
  4. D
    0.016 g

Correct answer

0.032 g

Explanation

Q = It = 0.965 × 100 = 96.5 C. m = (M/nF) × Q = (64/(2×96500)) × 96.5 = (64/193000) × 96.5 = 0.032 g.

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