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Question 310009
JEE Mathematics · Hard

Application of Derivatives: Optimization MCQ

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OptimizationHardQuestion 310009

Question

The minimum value of f(x) = x + 1/x for x > 0 is:
  1. A
    2
    Correct
  2. B
    1
  3. C
    0
  4. D
    3

Correct answer

2

Explanation

f'(x) = 1 − 1/x² = 0 → x = 1. f''(x) = 2/x³ > 0 → minimum at x = 1. f(1) = 1 + 1 = 2.

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