JEE MainHardQuestion 310010
Question
The maximum area of a rectangle with perimeter 20 m is:
- A25 m²Correct
- B20 m²
- C100 m²
- D10 m²
Correct answer
25 m²
Explanation
Let sides be x and y: 2(x+y) = 20 → x+y = 10. Area A = xy. By AM-GM: xy ≤ ((x+y)/2)² = 25. Maximum area = 25 m² when x = y = 5 (square).