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Question 390005
JEE Mathematics · Medium

Parabola: Normal to parabola MCQ

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Normal to parabolaMediumQuestion 390005

Question

The normal to y² = 4ax at (at², 2at) has slope:
  1. A
    −t
    Correct
  2. B
    t
  3. C
    1/t
  4. D
    −1/t

Correct answer

−t

Explanation

Tangent at (at², 2at) has slope = 1/t (from differentiating y² = 4ax: dy/dx = 2a/y = 1/t). Normal slope = −1/(tangent slope) = −t.

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