Chord of contactMediumQuestion 390006
Question
From external point (h, k) to y² = 4ax, the chord of contact is:
- Aky = 2a(x + h)Correct
- Bky = 2ax + h
- Cy = kx + h
- Dky = 2ah + x
Correct answer
ky = 2a(x + h)
Explanation
Chord of contact from (h,k) to y²=4ax: T = 0 → ky = 2a(x + h). This is the equation of the chord joining the two points of tangency.