Equation of lineMediumQuestion 350005
Question
The symmetric form of the line through (x₁,y₁,z₁) with direction ratios a,b,c is:
- A(x−x₁)/a = (y−y₁)/b = (z−z₁)/cCorrect
- Bx/a = y/b = z/c
- Cax+by+cz=0
- D(x,y,z)=(x₁,y₁,z₁)+t(a,b,c)
Correct answer
(x−x₁)/a = (y−y₁)/b = (z−z₁)/c
Explanation
Symmetric form (Cartesian): (x−x₁)/a = (y−y₁)/b = (z−z₁)/c = t. Each equation set equal to parameter t gives the three parametric equations.