Equation of planeMediumQuestion 350006
Question
The equation of a plane with normal vector (a, b, c) passing through (x₁,y₁,z₁) is:
- Aa(x−x₁)+b(y−y₁)+c(z−z₁)=0Correct
- Bax+by+cz=0
- Cx/a+y/b+z/c=1
- Da²+b²+c²=1
Correct answer
a(x−x₁)+b(y−y₁)+c(z−z₁)=0
Explanation
A plane with normal n⃗ = (a,b,c) passing through point (x₁,y₁,z₁): a(x−x₁)+b(y−y₁)+c(z−z₁) = 0.