Advanced — Inelastic ChainHardQuestion 30573
Question
In a chain of perfectly inelastic collisions (mass m hits mass m, hits mass m, ..., n times total), the final speed of the last mass in terms of initial v₀ is:
- Av₀/nCorrect
- Bv₀/2ⁿ
- Cv₀/(n!)
- Dv₀×n
Correct answer
v₀/n
Explanation
Each time m hits nm at rest in a chain of perfectly inelastic collisions, speed reduces by factor 1/(n+1). But for sequential collisions: after 1st collision, speed = v₀/2. After 2nd, 2m hits 2m at rest: speed remains v₀/2? No — it's more complex. For sequential individual collisions: final speed = v₀/n.