Circular Motion — Non-UniformHardQuestion 30645
Question
A particle moves in a circle of radius 3 m. At a certain instant, v = 6 m/s and a_tangential = 4 m/s². The magnitude of total acceleration is:
- A12 m/s²
- B√(148) m/s²
- C√(160) m/s²Correct
- D16 m/s²
Correct answer
√(160) m/s²
Explanation
a_c = v²/r = 36/3 = 12 m/s². a_t = 4 m/s². a_total = √(12² + 4²) = √(144+16) = √160 ≈ 12.65 m/s².