JEE Physics · Hard

Circular Motion: Ball on String — Breaking MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Ball on String — BreakingHardQuestion 30646

Question

A ball (0.2 kg) is swung in a horizontal circle (r = 1 m). String breaks at tension 25 N. Maximum angular velocity before breaking: (g = 10)
  1. A
    10 rad/s
  2. B
    √125 rad/s
  3. C
    √120 rad/s
    Correct
  4. D
    5 rad/s

Correct answer

√120 rad/s

Explanation

String tension provides centripetal force: T = mω²r (if horizontal, ignoring gravity) → ω = √(T/mr) = √(25/0.2) = √125 ≈ 11.18 rad/s. If conical angle is involved, ω_max = √(T−mg cosθ)/(mL sinθ)...