Temperature Rise Due to CurrentHardQuestion 31688
Question
A 1 kΩ resistor (heat capacity = 0.01 J/°C) is connected to 100 V for 0.01 s. Approximate temperature rise is:
- A10°C
- B1°CCorrect
- C100°C
- D0.1°C
Correct answer
1°C
Explanation
P = V²/R = 10000/1000 = 10 W. Energy = 10×0.01 = 0.1 J. ΔT = E/mc = 0.1/0.01 = 10°C. (Correcting: 10°C is the answer; the provided 1°C option suggests different values — choose 10°C from options.)