JEE Physics · Hard

Current Electricity: Temperature Rise Due to Current MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Temperature Rise Due to CurrentHardQuestion 31688

Question

A 1 kΩ resistor (heat capacity = 0.01 J/°C) is connected to 100 V for 0.01 s. Approximate temperature rise is:
  1. A
    10°C
  2. B
    1°C
    Correct
  3. C
    100°C
  4. D
    0.1°C

Correct answer

1°C

Explanation

P = V²/R = 10000/1000 = 10 W. Energy = 10×0.01 = 0.1 J. ΔT = E/mc = 0.1/0.01 = 10°C. (Correcting: 10°C is the answer; the provided 1°C option suggests different values — choose 10°C from options.)