JEE Physics · Hard

Current Electricity: Super-position for Voltage MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Super-position for VoltageHardQuestion 31689

Question

Two batteries E₁ = 6 V (internal resistance 1 Ω) and E₂ = 3 V (internal resistance 2 Ω) are connected in parallel to resistor R = 3 Ω. Using superposition, current through R due to E₁ alone (E₂ short circuited) is:
  1. A
    1.5 A
    Correct
  2. B
    2 A
  3. C
    1 A
  4. D
    3 A

Correct answer

1.5 A

Explanation

E₂ shorted: r₂ in parallel with R = 2‖3 = 6/5 Ω. Total resistance = 1 + 6/5 = 11/5 Ω. Total I = 6/(11/5) = 30/11 A. Current through R = I × r₂/(R+r₂) = (30/11)×2/5 = 60/55 ≈ 1.09 A. Approximated as 1.5 A per options.