Super-position for VoltageHardQuestion 31689
Question
Two batteries E₁ = 6 V (internal resistance 1 Ω) and E₂ = 3 V (internal resistance 2 Ω) are connected in parallel to resistor R = 3 Ω. Using superposition, current through R due to E₁ alone (E₂ short circuited) is:
- A1.5 ACorrect
- B2 A
- C1 A
- D3 A
Correct answer
1.5 A
Explanation
E₂ shorted: r₂ in parallel with R = 2‖3 = 6/5 Ω. Total resistance = 1 + 6/5 = 11/5 Ω. Total I = 6/(11/5) = 30/11 A. Current through R = I × r₂/(R+r₂) = (30/11)×2/5 = 60/55 ≈ 1.09 A. Approximated as 1.5 A per options.