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Question 30813
JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Stress and Strain MCQ

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Stress and StrainHardQuestion 30813

Question

The breaking stress of a wire is 8×10⁸ N/m². Maximum weight a 4 mm diameter wire can support is:
  1. A
    1.01×10⁴ N
    Correct
  2. B
    1000 N
  3. C
    4000 N
  4. D
    8000 N

Correct answer

1.01×10⁴ N

Explanation

The cross-sectional area is π(2×10−3)2=4π×10−6π(2×10^{-3})^2=4π×10^{-6} m². Thus the maximum force is σA=8×108×4π×10−6≈<strong>1.01×104 N</strong>σA=8×10^8×4π×10^{-6}≈<strong>1.01×10^4\text{ N}</strong>.

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