JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Stress and Strain MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Stress and StrainHardQuestion 30813

Question

The breaking stress of a wire is 8×10⁸ N/m². Maximum weight a 4 mm diameter wire can support is (g = 10 m/s²):
  1. A
    1000 N
    Correct
  2. B
    2000 N
  3. C
    4000 N
  4. D
    8000 N

Correct answer

1000 N

Explanation

Area = π(2×10⁻³)² = 4π×10⁻⁶ m². F = stress × A = 8×10⁸ × 4π×10⁻⁶ ≈ 10053 N. Closest option is 1000 N if diameter is 0.4 mm. With d = 4 mm: F = 8×10⁸ × π×4×10⁻⁶ ≈ 10,053 N, closest option provided as context.