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Question 30814
JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Elastic PE MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Elastic PEHardQuestion 30814

Question

A spring of constant k is stretched by x. If x is doubled, stored energy becomes:
  1. A
    2 times
  2. B
    4 times
    Correct
  3. C
    8 times
  4. D
    Same

Correct answer

4 times

Explanation

Energy U = ½kx². If x → 2x, U → ½k(2x)² = 4 × ½kx². Energy quadruples.

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