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Question 30819
JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Elastic PE MCQ

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Elastic PEHardQuestion 30819

Question

Two springs (constants k₁ = 2k, k₂ = k) are connected in series and stretched by force F. Ratio of energy stored E₁:E₂ is:
  1. A
    2:1
  2. B
    1:2
    Correct
  3. C
    1:1
  4. D
    4:1

Correct answer

1:2

Explanation

In series, force is same. Energy = F²/(2k). E₁/E₂ = k₂/k₁ = k/(2k) = 1:2.

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