JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Young's Modulus MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Young's ModulusHardQuestion 30820

Question

A steel wire (Y = 2×10¹¹ Pa) of length 2 m and area 2×10⁻⁶ m² is loaded with 200 N. Extension is:
  1. A
    0.5 mm
  2. B
    1 mm
    Correct
  3. C
    2 mm
  4. D
    4 mm

Correct answer

1 mm

Explanation

ΔL = FL/(AY) = 200 × 2 / (2×10⁻⁶ × 2×10¹¹) = 400 / (4×10⁵) = 10⁻³ m = 1 mm.