ConductionMediumQuestion 30866
Question
Two slabs (same area, same thickness) of conductivities k₁ and k₂ are in series. Effective conductivity is:
- Ak₁ + k₂
- B(k₁k₂)/(k₁+k₂)
- C2k₁k₂/(k₁+k₂)Correct
- D(k₁+k₂)/2
Correct answer
2k₁k₂/(k₁+k₂)
Explanation
Thermal resistance in series: R = R₁ + R₂. For equal thickness L: k_eff = 2k₁k₂/(k₁+k₂) (harmonic mean).