ConductionMediumQuestion 30867
Question
Two slabs (same area, same thickness) of conductivities k₁ and k₂ are in parallel. Effective conductivity is:
- A(k₁+k₂)/2Correct
- B2k₁k₂/(k₁+k₂)
- Ck₁k₂
- Dk₁+k₂
Correct answer
(k₁+k₂)/2
Explanation
Same temperature difference, conductances add: k_eff = (k₁+k₂)/2 (arithmetic mean) for equal areas.