JEE Physics · Hard

Electromagnetic Waves and Wave Optics: Coherence Length MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Coherence LengthHardQuestion 20239

Question

A sodium lamp emits two closely spaced wavelengths 589.0 nm and 589.6 nm. They produce interference fringes that disappear and reappear. Fringes disappear (minima of visibility) when:
  1. A
    All fringes overlap completely
  2. B
    Bright fringes of one wavelength coincide with dark fringes of the other
    Correct
  3. C
    Path difference equals coherence length
  4. D
    Intensity is zero everywhere

Correct answer

Bright fringes of one wavelength coincide with dark fringes of the other

Explanation

When n₁λ₁ = (n₁ + ½)λ₂, bright fringe of λ₁ overlaps dark fringe of λ₂ → fringes disappear (minimum visibility). This occurs at path difference Δ = λ₁λ₂/(2|λ₁−λ₂|) ≈ λ̄²/(2Δλ). This phenomenon is used to measure wavelength separation (coherence length measurement).