JEE Physics · Hard

Electromagnetic Waves and Wave Optics: Lloyd's Mirror MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Lloyd's MirrorHardQuestion 20240

Question

In Lloyd's mirror experiment, the fringe at the edge (zero path difference) is:
  1. A
    Bright (constructive)
  2. B
    Dark (destructive) due to phase change on reflection
    Correct
  3. C
    Absent
  4. D
    White fringes only

Correct answer

Dark (destructive) due to phase change on reflection

Explanation

The reflected ray undergoes a phase change of π (half wavelength) on reflection from the denser glass mirror. At zero path difference, the direct and reflected beams are π out of phase → destructive interference → dark fringe at the edge. This confirms the phase change on reflection.