Electric FieldEasyQuestion 31462
Question
A charge of 2 μC is placed in a field of 1000 N/C. Force on it is:
- A0.002 NCorrect
- B0.5 N
- C2000 N
- D2 N
Correct answer
0.002 N
Explanation
F = qE = 2×10⁻⁶ × 1000 = 2×10⁻³ N = 0.002 N.
JEE Physics · Easy
Electrostatics: Electric Field MCQ
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