Gauss's LawMediumQuestion 31464
Question
Charge +Q is placed at centre of a spherical shell of radius R. Charge on inner surface of shell is:
- A+Q
- B−QCorrect
- CZero
- D+2Q
Correct answer
−Q
Explanation
Gauss's law with surface inside shell conductor: E = 0 inside conductor → charge on inner surface = −Q to cancel the field.