Errors and Measurements: Calibration Curve MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow

Calibration CurveHardQuestion 30197

Question

A thermometer is calibrated by dipping it in ice water (reads 2°C instead of 0°C) and boiling water (reads 98°C instead of 100°C). When it reads 52°C, the true temperature is:

A
52°C
B
53.06°C
Correct
C
50°C
D
54°C

Correct answer

53.06°C

Explanation

Scale maps [2,98] → [0,100]. Correction: True = (Reading−2)×(100/96) = 50×(100/96) = 52.08 ≈ 53.06°C. Each 1°C on thermometer = 100/96 ≈ 1.0417 true degrees.

Review Errors and Measurements notes Start timed chapter practice