Kepler's 3rd NumericalMediumQuestion 30747
Question
A satellite has orbital radius 4 times that of another satellite with period 8 days. Period of the outer satellite is:
- A32 days
- B64 daysCorrect
- C16 days
- D8 days
Correct answer
64 days
Explanation
T ∝ r^(3/2). T₂/T₁ = (4r/r)^(3/2) = 4^(3/2) = 8. T₂ = 8×8 = 64 days.