Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Laws of Motion and Friction/
Question 30220
JEE Physics · Hard

Laws of Motion and Friction: Law of Conservation of Momentum MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Law of Conservation of MomentumHardQuestion 30220

Question

A 60 kg person stands in a 40 kg boat. If the person walks at 2 m/s east, the boat moves:
  1. A
    1.33 m/s west
  2. B
    3 m/s west
    Correct
  3. C
    1 m/s west
  4. D
    2 m/s west

Correct answer

3 m/s west

Explanation

Conservation of momentum (initial momentum = 0): 60×2 + 40×v_boat = 0. v_boat = −120/40 = −3 m/s (west).

Review Laws of Motion and Friction notesStart timed chapter practice