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Question 30221
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Laws of Motion and Friction: FBD — Elevator MCQ

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FBD — ElevatorEasyQuestion 30221

Question

A 60 kg person stands in an elevator accelerating upward at 2 m/s². The apparent weight (normal force) is: (g = 10 m/s²)
  1. A
    480 N
  2. B
    600 N
  3. C
    720 N
    Correct
  4. D
    540 N

Correct answer

720 N

Explanation

N − mg = ma → N = m(g+a) = 60(10+2) = 720 N.

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