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Question 30278
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Laws of Motion and Friction: Advanced — Apparent Weight MCQ

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Advanced — Apparent WeightHardQuestion 30278

Question

At the equator, the apparent weight of a person (mass m) due to Earth's rotation (radius R, angular velocity ω) is:
  1. A
    mg
  2. B
    mg − mω²R
    Correct
  3. C
    mg + mω²R
  4. D
    mω²R

Correct answer

mg − mω²R

Explanation

At the equator, part of gravity provides centripetal acceleration: N = mg − mω²R. This is the apparent weight measured by a spring scale.

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