JEE Physics · Hard

Principles of Communication: Communication System MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Communication SystemHardQuestion 20320

Question

A digital telephone channel has bandwidth 4 kHz and SNR = 255. Using Shannon's formula the maximum bit rate is:
  1. A
    32 kbps
    Correct
  2. B
    64 kbps
  3. C
    32.7 kbps
  4. D
    8 kbps

Correct answer

32 kbps

Explanation

C = B log₂(1+SNR) = 4000 × log₂(256) = 4000 × 8 = 32,000 bps = 32 kbps. Note log₂(256) = 8. In practice, voice is encoded at 64 kbps (PCM, G.711) within this channel — possible because PCM doesn't approach the Shannon limit; advanced codecs (G.729) achieve toll-quality at 8 kbps.