Communication SystemHardQuestion 20320
Question
A digital telephone channel has bandwidth 4 kHz and SNR = 255. Using Shannon's formula the maximum bit rate is:
- A32 kbpsCorrect
- B64 kbps
- C32.7 kbps
- D8 kbps
Correct answer
32 kbps
Explanation
C = B log₂(1+SNR) = 4000 × log₂(256) = 4000 × 8 = 32,000 bps = 32 kbps. Note log₂(256) = 8. In practice, voice is encoded at 64 kbps (PCM, G.711) within this channel — possible because PCM doesn't approach the Shannon limit; advanced codecs (G.729) achieve toll-quality at 8 kbps.