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Question 20256
JEE Physics · Hard

Semiconductors: Transistor — Collector Characteristics Analysis MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Transistor — Collector Characteristics AnalysisHardQuestion 20256

Question

In a BJT common-emitter circuit: V_CC = 10 V, R_C = 2 kΩ, β = 100. If I_B = 40 μA, find I_C and V_CE.
  1. A
    I_C = 4 mA, V_CE = 2 V
    Correct
  2. B
    I_C = 2 mA, V_CE = 6 V
  3. C
    I_C = 4 mA, V_CE = 10 V
  4. D
    I_C = 40 mA, V_CE = 0

Correct answer

I_C = 4 mA, V_CE = 2 V

Explanation

I_C = β × I_B = 100 × 40×10⁻⁶ = 4 mA. V_CE = V_CC − I_C × R_C = 10 − 4×10⁻³ × 2×10³ = 10 − 8 = 2 V. The transistor is in active mode (V_CE > V_CE,sat).

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