EnergyHardQuestion 31171
Question
Total energy of SHM is 0.1 J. When displacement is half the amplitude, PE is:
- A0.025 JCorrect
- B0.05 J
- C0.1 J
- D0.075 J
Correct answer
0.025 J
Explanation
PE = ½kx² = ½k(A/2)² = ¼ × ½kA² = E/4 = 0.1/4 = 0.025 J.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
PE = ½kx² = ½k(A/2)² = ¼ × ½kA² = E/4 = 0.1/4 = 0.025 J.