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Question 31172
JEE Physics · Hard

Simple Harmonic Motion: Simple Pendulum MCQ

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Simple PendulumHardQuestion 31172

Question

A pendulum of length 1 m swings with amplitude 4 cm. Maximum speed of bob is approximately (g = 10 m/s²):
  1. A
    0.12 m/s
    Correct
  2. B
    0.04 m/s
  3. C
    0.4 m/s
  4. D
    1.2 m/s

Correct answer

0.12 m/s

Explanation

ω = √(g/L) = √10 ≈ 3.16 rad/s. v_max = ωA = 3.16 × 0.04 ≈ 0.126 m/s ≈ 0.12 m/s.

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