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Question 31180
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Simple Harmonic Motion: SHM and Circular Motion MCQ

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SHM and Circular MotionHardQuestion 31180

Question

A particle moves in circle of radius R at angular speed ω. Projection on a diameter starts at x = R (t=0) and moves to x = 0 in time:
  1. A
    π/(2ω)
    Correct
  2. B
    π/ω
  3. C
    2π/ω
  4. D
    ω/π

Correct answer

π/(2ω)

Explanation

x = R cosωt. Reaches x = 0 when cosωt = 0 → ωt = π/2 → t = π/(2ω) = T/4.

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