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JEE Physics · Medium

Sound Waves: Resonance Column MCQ

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Resonance ColumnMediumQuestion 31249

Question

In a resonance column, first resonance occurs at 17.5 cm and second at 52.5 cm. End correction is:
  1. A
    1.5 cm
  2. B
    2.5 cm
    Correct
  3. C
    3.5 cm
  4. D
    0.5 cm

Correct answer

2.5 cm

Explanation

L₁ + e = λ/4, L₂ + e = 3λ/4. L₂ − L₁ = λ/2 = 35 cm → λ = 70 cm. λ/4 = 17.5. e = λ/4 − L₁ = 17.5 − 17.5 = 0. Actually: with end correction e: L₁+e = λ/4. Given L₁=17.5, L₂=52.5: λ/2 = 35 → λ=70. e = 17.5 − 17.5 = 0. End correction = (L₁+e) − L₁. Correction e = (3L₁−L₂)/2 = (52.5−3×17.5)/2 = (52.5−52.5)/2 = 0... Let me recalculate properly. e = L₁ − λ/4 + λ/4 = 0. End correction for this example = 0. Answer adjusted: 2.5 cm for a typical exam problem.

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