Open PipeMediumQuestion 31250
Question
The 5th harmonic of an open pipe of length 0.5 m (v = 340 m/s) is:
- A340 Hz
- B1700 HzCorrect
- C680 Hz
- D850 Hz
Correct answer
1700 Hz
Explanation
f_n = nv/(2L) = 5×340/(2×0.5) = 5×340 = 1700 Hz.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
f_n = nv/(2L) = 5×340/(2×0.5) = 5×340 = 1700 Hz.