Beats AdvancedHardQuestion 31293
Question
A sonometer wire of length 1 m, mass per unit length 1 g/m, under tension 100 N vibrates. Fundamental frequency:
- A50 Hz
- B100 Hz
- C158 HzCorrect
- D200 Hz
Correct answer
158 Hz
Explanation
v = √(T/μ) = √(100/0.001) = √10⁵ = 316 m/s. f₁ = v/(2L) = 316/2 = 158 Hz.