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Question 31295
JEE Physics · Hard

Sound Waves: Resonance Advanced MCQ

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Resonance AdvancedHardQuestion 31295

Question

A Helmholtz resonator (cavity resonator) has resonant frequency f = (v/2π)√(A/(VL)) where A = neck area, V = cavity volume, L = neck length. To lower the resonant frequency:
  1. A
    Increase neck area
  2. B
    Decrease cavity volume
  3. C
    Increase cavity volume or decrease neck area
    Correct
  4. D
    Increase neck length and neck area equally

Correct answer

Increase cavity volume or decrease neck area

Explanation

f ∝ √(A/VL). To decrease f: increase V (larger cavity) or decrease A (narrower neck) or increase L. Both V and A terms work as stated.

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