Wave SpeedHardQuestion 31312
Question
Two strings of same length, same tension: string A (μ_A) and string B (μ_B = 4μ_A). Ratio of fundamental frequencies f_A:f_B is:
- A1:2
- B2:1Correct
- C1:4
- D4:1
Correct answer
2:1
Explanation
f ∝ v ∝ 1/√μ. f_A/f_B = √(μ_B/μ_A) = √4 = 2. So f_A:f_B = 2:1.