JEE Physics · Hard

Waves on String: Reflection MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
ReflectionHardQuestion 31313

Question

Transverse velocity of string element at x, t is:
  1. A
    Wave speed v
  2. B
    ∂y/∂t = Aω cos(ωt−kx)
    Correct
  3. C
    ∂y/∂x
  4. D
    A×k×v

Correct answer

∂y/∂t = Aω cos(ωt−kx)

Explanation

Transverse particle velocity = ∂y/∂t. For y = A sin(ωt−kx): ∂y/∂t = Aω cos(ωt−kx). Max transverse speed = Aω (not wave speed v).