PowerHardQuestion 31368
Question
Two strings of same tension. String 1 (μ₁ = μ) carries wave of amplitude A and frequency f. String 2 (μ₂ = 4μ) carries wave at same A and f. Ratio P₁:P₂:
- A1:2Correct
- B2:1
- C1:4
- D1:√2
Correct answer
1:2
Explanation
P = ½μω²A²v = ½μω²A²√(T/μ) = ½ω²A²√(μT). P ∝ √μ. P₁/P₂ = √(μ/4μ) = 1/2. So P₁:P₂ = 1:2.