ReflectionHardQuestion 31377
Question
A wave in a lighter string (μ₁) reaches a junction with heavier string (μ₂ = 4μ₁). Reflection amplitude ratio:
- A1/3Correct
- B1/2
- C1/4
- D2/3
Correct answer
1/3
Explanation
v₁ = √(T/μ₁), v₂ = √(T/4μ₁) = v₁/2. r/A = (v₂−v₁)/(v₂+v₁) = (v₁/2−v₁)/(v₁/2+v₁) = (−v₁/2)/(3v₁/2) = −1/3. Magnitude = 1/3.