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Question 31378
JEE Physics · Hard

Waves on String: Harmonics MCQ

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HarmonicsHardQuestion 31378

Question

String A (2 m, vibrates at 100 Hz in fundamental). String B of same material, same cross section, 1 m, tension 4 times. Fundamental of B:
  1. A
    200 Hz
  2. B
    400 Hz
    Correct
  3. C
    100 Hz
  4. D
    50 Hz

Correct answer

400 Hz

Explanation

v ∝ √T. v_B = v_A√4 = 2v_A. L_B = 1 m = L_A/2. f_B = v_B/(2L_B) = 2v_A/(2×1) = v_A = v_A/(2×2)×4 = 4×f_A = 400 Hz.

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