Inelastic Collision — Energy LossHardQuestion 30438
Question
Two equal masses (each m) collide head-on. One moves at v, the other at rest. After perfectly inelastic collision, energy lost is:
- A½mv²
- Bmv²/4Correct
- Cmv²/2
- Dmv²
Correct answer
mv²/4
Explanation
After collision: v_f = mv/(2m) = v/2. KE_before = ½mv². KE_after = ½(2m)(v/2)² = ¼mv². Energy lost = ½mv² − ¼mv² = ¼mv².