PE FunctionHardQuestion 30453
Question
A particle has PE U(x) = 4x² − 2x. The equilibrium position and force at x = 1 m are:
- Ax = 0.25 m; F(1 m) = −6 NCorrect
- Bx = 1 m; F(1 m) = 6 N
- Cx = 0.5 m; F(1 m) = −6 N
- Dx = 0.25 m; F(1 m) = 0
Correct answer
x = 0.25 m; F(1 m) = −6 N
Explanation
F = −dU/dx = −(8x − 2). At equilibrium, F = 0, so 8x = 2 and x = 0.25 m. At x = 1 m, F = −(8 − 2) = −6 N.