Work — Friction on InclineMediumQuestion 30454
Question
A block pushed up a rough incline (θ=30°, μₖ=0.3, d=5m, m=2kg). Work done by friction is: (g=10, sin30°=0.5, cos30°=0.866)
- A−25.98 JCorrect
- B+25.98 J
- C−15 J
- D+15 J
Correct answer
−25.98 J
Explanation
Normal force = mg cosθ = 2×10×0.866 = 17.32 N. Friction = μₖN = 0.3×17.32 = 5.196 N. W_friction = −5.196×5 = −25.98 J (opposing upward motion).