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Work, Power and Energy: JEE — Horizontal Projection KE MCQ

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JEE — Horizontal Projection KEMediumQuestion 30466

Question

A ball is projected horizontally with KE = E₀. At the lowest point of its trajectory (height H below launch): KE equals:
  1. A
    E₀ + mgH
    Correct
  2. B
    E₀ − mgH
  3. C
    E₀
  4. D
    2E₀

Correct answer

E₀ + mgH

Explanation

By energy conservation: KE_final = KE_initial + ΔPE = E₀ + mgH.

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