JEE — Spring-Block Period and EnergyHardQuestion 30467
Question
A block-spring system oscillates. At equilibrium position, the PE is minimum and KE is maximum. If amplitude is A, the maximum KE is:
- AkA²
- B½kA²Correct
- CkA²/4
- D2kA²
Correct answer
½kA²
Explanation
At equilibrium, all energy is kinetic: KE_max = Total energy = ½kA².