Buffer numericHardQuestion 24086
Question
If [salt]/[base] = 100 in a basic buffer, then pOH is:
- ApKb + 2Correct
- BpKb - 2
- CpKb only
- D14 - pKb
Correct answer
pKb + 2
Explanation
Log 100 = 2.
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
If [salt]/[base] = 100 in a basic buffer, then pOH is:
Log 100 = 2.